\(\varepsilon=\mathrm{B} \ell \mathrm{v}=5 \times 10^{-4}\, \mathrm{V}\)
So total resistance
\(\mathrm{R}=\frac{4}{3}+1.7 \approx 3\, \Omega\)
\(\therefore \quad \mathrm{i}=\frac{\varepsilon}{\mathrm{R}} \approx 166\, \mu \mathrm{A} \approx 170\, \mu \mathrm{A}\)