\(\frac{x-(y+5)}{1}+\frac{x-2}{2}+\frac{x-0}{2}=0\)
Junction law at \(B\),
\(\frac{y+5-x}{1}+\frac{y-0}{1}+\frac{y-2}{1}=0\)
On solving equation (1) and Equation (2) \(x =3\)
\(y=0\)
At \(D\) junction
\(I_1 =i_1+i_2\)
\(I_1 =\frac{y-0}{1}+\frac{x-0}{2}\)
\(=\frac{0-0}{1}+\frac{3-0}{2}\)
\(I_1 =1.5\,A\)