c
(c) By drawing the free body diagram of point \(B\)

Let the tension in the section \(BC\) and \(BF\) are \({T_1}\) and \({T_2}\) respectively.
From Lami's theorem

\(\frac{{{T_1}}}{{\sin 120^\circ }} = \frac{{{T_2}}}{{\sin 120^\circ }} = \frac{T}{{\sin 120^\circ }}\)

\(⇒\) \(T = {T_1} = {T_2} = 10\;N.\)