$A,B,C$ અને $P,Q,R$ ની દરેક કિમંત માટે , $\left| {\,\begin{array}{*{20}{c}}{\cos (A - P)}&{\cos (A - Q)}&{\cos (A - R)}\\{\cos (B - P)}&{\cos (B - Q)}&{\cos (B - R)}\\{\cos (C - P)}&{\cos (C - Q)}&{\cos (C - R)}\end{array}\,} \right| =. . . $
A$0$
B$\cos A\cos B\cos C$
C$sin$ $A$ $sin$ $B$ $sin$ $C$
D$cos$ $P$ $cos$ $Q$ $cos$ $R$
IIT 1994, Diffcult
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A$0$
a (a) The determinant can be expanded as
$\left| {\begin{array}{*{20}{c}}{\cos A\cos P + \sin A\sin P}&{\cos A\cos Q + \sin A\sin Q}&{}\\{\cos B\cos P + \sin B\sin P}&{\cos B\cos Q + \sin B\sin Q}&{}\\{\cos C\cos P + \sin C\sin P}&{\cos C\cos Q + \sin C\sin Q}&{}\end{array}} \right.$$\left. {\begin{array}{*{20}{c}}{\cos A\cos R + \sin A\sin R}\\{\cos B\cos R + \sin B\sin R}\\{\cos C\cos R + \sin C\sin R}\end{array}\,} \right|$
This determinant can be written as $8$ determinants and the value of each of these $8$ determinants is zero;
e.g., $\cos P\cos Q\cos R{\rm{ }}\left| {\,\begin{array}{*{20}{c}}{\cos A}&{\cos A}&{\cos A}\\{\cos B}&{\cos B}&{\cos B}\\{\cos C}&{\cos C}&{\cos C}\end{array}\,} \right| = 0$
Similarly other determinants can be shown zero.
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જો શ્રેણિક $A$ અને $B$ એ $A\, = \,\left[ {\begin{array}{*{20}{c}} 3&2 \\ 2&1 \end{array}} \right]$ અને $B\, = \,\left[ {\begin{array}{*{20}{c}} 3&1 \\ 7&3 \end{array}} \right]$ મુજબ આપેલ છે તો $\text{det} \,(2A^9B^{-1})$ ની કિમંત મેળવો.
અહી $I$ એ $2 \times 2$ કક્ષાનો એકમ શ્રેણીક છે અને $P=\left[\begin{array}{cc}2 & -1 \\ 5 & -3\end{array}\right] $ છે. તો $n \in N$ ની કિમંત મેળવો કે જેથી $P^n =5 I -8 P$ થાય.
If $1,\omega ,{\omega ^2}$ are the cube roots of unity, then $\Delta = \left| {\,\begin{array}{*{20}{c}}1&{{\omega ^n}}&{{\omega ^{2n}}}\\{{\omega ^n}}&{{\omega ^{2n}}}&1\\{{\omega ^{2n}}}&1&{{\omega ^n}}\end{array}\,} \right|$ is equal to