ABCD is a cyclic quadrilateral in a circle with centre O. If ∠ADC = 130°; find ∠ BAC.
Exercise 17 (A) | Q 13 | Page 258
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Here ∠ACB = 90°
(Angle in a semicircle is right angle)
Also, ∠ABC = 180° -∠ADC = 180° - 130° = 50°
(pair of opposite angles in a cy clic quadrilateral are supplementary)
By angle sum property of right triangle ACB,
∠BAC = 90° - ∠ABC = 90° - 50° = 40°
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