After switch is closed, current drawn from the battery is (in $A$)
A$6$
B$1.5$
C$3$
D$4$
AIIMS 2019, Medium
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C$3$
c Consider the circuit as shown below.
The equivalent resistance of the circuit is,
$R_{ eq }=1 \Omega+\frac{6 \times 3}{6+3} \Omega$
$=3 \Omega$
The current is calculated as,
$i=\frac{V}{R_{ eq }}$
$=\frac{9 V }{3 \Omega}$
$=3 A$
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