પ્રક્રિયા $3 CaO +2 Al \rightarrow 3 Ca + Al _{2} O _{3}$ માટે પ્રમાણિત પ્રક્રિયા એન્થાલ્પી $\Delta_{ r } H ^{0=}$ .......... $kJ$
\(3 CaO + Al \rightarrow Al _{2} O _{3}+3 Ca\)
Now, \(\Delta_{ r } H ^{\circ}=\Sigma \Delta_{ f } H _{\text {Products }}^{\circ}-\Sigma \Delta_{ f } H _{\text {Reactants }}^{\circ}\)
\(=[1 \times(-1675)+3 \times 0]-[3 \times(-635)+2 \times 0]\)
\(=+230 kJ mol ^{-1}\)
$(i)\,\,{C_{12}}{H_{22}}{O_{11}}\,\, + \,\,12{O_2}\,\, \to \,\,12\,\,C{O_2}\, + \,\,11{H_2}O,\,\,\,\,\,\,\,\,\,\,\,\,\Delta H\,\, = \,\, - 5200.7\,kJ\,mo{l^{ - 1}} $
$(ii)\,\,C\,\, + \,\,{O_2}\, \to \,\,C{O_2},\,\,\,\,\,\,\,\,\,\,\,\,\Delta H\,\, = \,\, - \,394.5\,\,kJ\,\,mo{l^{ - 1}}$
$(iii)\,\,{H_2}\,\, + \,\frac{1}{2}{O_2}\,\, \to \,\,\,{H_2}O,\,\,\,\,\,\,\,\,\,\Delta H\,\, = \,\, - \,285.8\,kJ\,\,mo{l^{ - 1}}$