$CaO_{(s)}\,\, + \,\,{H_2}O_{(l)}\,\, \to \,\,Ca{(OH)_2}_{(s)}\,;\,\,\,........(i)$ $\,\Delta {H_{1.8\,^oC}} = \,\, - \,\,15.26\,\,K\,cal$
$H_2O_{(l)}\,$ $ \to $ ${H_{2{(g)}}}$ $+$ $\frac{1}{2}O_{2(g)}$ $\,\Delta {H_{1.8\,^oC}} = \,\, - \,\,68.37\,\,K\,cal$
$Ca_{(s)} + \frac{1}{2}O_{2(g)} = CaO_{(s)}$ $\,\Delta {H_{1.8\,^oC}} = \,\, \,\,-151.80\,\,K\,cal$
$CH _{4}+2 O _{2} \rightarrow CO _{2}+2 H _{2} O (\Delta H =-891 kJ / mol)$
$H _{2} F _{2( g )} \rightarrow H _{2( g )}+ F _{2( g )}$
$\Delta U =-59.6\,kJ\,mol ^{-1}$ $27^{\circ}\,C$ પર,
ઉપરની પ્રક્રિયામાં એન્થાલ્પીમાં થતો ફેરફાર $(-)......\,kJ\, mol ^{-1}$ [નજીકનો પૂર્ણાંક]
(આપેલ : $\left.R =8.314 \,J\, K ^{-1} \,mol ^{-1}\right)$
$Fe_2O_{3(s)} + 3CO_{(g)} \rightarrow 2Fe_{(s)} + 3CO_{2(g)};$ $\Delta H = - 26.8\, kJ$
$FeO_{(s)} + CO_{(g)} \rightarrow Fe_{(s)} + CO_{2(g)} \, ;$ $\Delta H = - 16.5\, kJ$
નીચેની પ્રક્રિયા માટે $\Delta H$ નું મૂલ્ય કેટલા ............. $\mathrm{kJ}$ થશે ?
$Fe_2O_{3(s)} + CO_{(g)} \rightarrow 2FeO_{(s)} + CO_{2(g)}$ is
${H_2}O(l)$ $\rightleftharpoons$ ${H_2}O(g)$