An ammeter of $100$ $\Omega$ resistance gives full deflection for the current of $10^{-5} \,amp$. Now the shunt resistance required to convert it into ammeter of $1\, amp$. range, will be
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(c) $\frac{i}{{{i_g}}} = 1 + \frac{G}{S} \Rightarrow \frac{1}{{{{10}^{ - 5}}}} = 1 + \frac{{100}}{S}$$ \Rightarrow \,\,S \approx \frac{{100}}{{{{10}^5}}} = {10^{ - 3}}\,\Omega $.
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