MCQ
An amount of solid $N{H_4}HS$ is placed in a flask already containing ammonia gas at a certain temperature and $0.50$ $atm.$ pressure. Ammonium hydrogen sulphide decomposes to yield $N{H_3}$ and ${H_2}S$ gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to $0.84$ $atm$. The equilibrium constant for $N{H_4}HS$ decomposition at this temperature is
  • A
    $0.3$
  • B
    $0.18$
  • C
    $0.17$
  • $0.11$

Answer

Correct option: D.
$0.11$
(d) $\mathop {\mathop {N{H_4}HS}\limits_{\rm{a}} }\limits_{{\rm{a}} - {\rm{x}}} $ $ \rightleftharpoons $ $\mathop {\mathop {N{H_{3\,(g)}} + {H_2}{S_{(g)}}}\limits_{0.5{\rm{atm}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} }\limits_{0.5 + {\rm{x}}\,\,\,\,\,\,\,\,\,\,\,{\rm{x}}\,\,\,\,\,\,} $

Total pressure $ = 0.5 + 2x = 0.84$

i.e., $x = 0.17$

${K_p} = {P_{N{H_3}}}.{P_{{H_2}S}}$ $ = (0.67).\,(0.17)=0.1139$

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