An electron in a hydrogen atom revolves around its nucleus with a speed of $6.76 \times 10^6\,ms ^{-1}$ in an orbit of radius $0.52\,\mathring A$. The magnetic field produced at the nucleus of the hydrogen atom is $......T$.
JEE MAIN 2023, Medium
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Magnetic field due to moving charge
$B =\frac{\mu_0}{4 \pi} \frac{ q \sin \theta}{ r ^2}$
$B =\frac{\mu_0}{4 \pi} \frac{ ev \sin (\pi / 2)}{ r ^2}$
$B =\frac{10^{-7} \times 1.6 \times 10^{-19} \times 6.76 \times 10^6}{0.52 \times 0.52 \times 10^{-20}}$
$B =40\,T$
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