An electron is made to enters symmetrically between two parallel … - Vidyadip

MCQ

An electron is made to enters symmetrically between two parallel and equally but oppositely charged metal plates, each of 10 cm length. The electron emerges out of the field region with a horizontal component of velocity $10^6 m / s$. If the magnitude of the electric between the plates is 9.1 $V / cm$, then the vertical component of velocity of electron is
(mass of electron $=9.1 \times 10^{-31} kg$ and charge of electron $=1.6 \times 10^{-19} C$ )

A
$1 \times 10^6 m / s$
B
0
C
$16 \times 10^6 m / s$
D
$16 \times 10^4 m / s$

✓

Answer

(C) $16 \times 10^6 m / s$
Sol .

$\begin{array}{l}\Rightarrow t =\frac{\ell}{ V _{ x }}=\frac{10 \times 10^{-2}}{10^6}=10^{-7} \\ \Rightarrow V_{ y }= u _{ y }+ a _{ y } t \\ \Rightarrow V _{ y }=0+\frac{ eE }{ m } \times 10^{-7} \\ \Rightarrow V_{ y }=\frac{1.6 \times 10^{-19}}{9.1 \times 10^{-31}} \times 9.1 \times 10^{-2} \times 10^{-7} \\ \Rightarrow V_y=16 \times 10^6\end{array}$

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