An electron revolves around nucleus with rotational frequency $'f'$ in circular orbit, due to this magnetic induction produced at nucleus position is $'B'$ then radius of circular orbit is directly proportional to
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$\mathrm{I}=\mathrm{Fe} \Rightarrow \mathrm{B}=\frac{\mu_{0} \mathrm{I}}{2 \mathrm{R}}=\frac{\mu_{0}}{2 \mathrm{R}} \cdot \mathrm{Fe} \Rightarrow \mathrm{R} \propto \frac{\mathrm{F}}{\mathrm{B}}$
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