$n_{1}=\frac{330}{330-110} n=(3 / 2) n$
when source is receding from the observer,
$n_{2}=\frac{330}{330+110} n=(3 / 4) n$
$\frac{n_{1}}{n_{2}}=\frac{(3 / 2)}{(3 / 4)}=\frac{2}{1}$
${y}=1.0\, {mm} \cos \left(1.57 \,{cm}^{-1}\right) {x} \sin \left(78.5\, {s}^{-1}\right) {t}$
The node closest to the origin in the region ${x}>0$ will be at ${x}=\ldots \ldots \ldots\, {cm}$