A closely wounded circular coil of radius $5\,cm$ produces a magnetic field of $37.68 \times 10^{-4}\,T$ at its center. The current through the coil is $......A$. [Given, number of turns in the coil is $100$ and $\pi=3.14]$
JEE MAIN 2022, Easy
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$B _{\text {centre}}=\frac{N \mu_{0} I}{2 R }$

$37.68 \times 10^{-4}=\frac{100 \times 4 \pi \times 10^{-7} \times I }{2 \times 5 \times 10^{-2}}$

$I =3\,A$

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