Question
An ionic hydride of groups has sufficiently covalent character. It is used to form hydrides of other elements of group 13 which are useful reducing agent. Write the formula this hydride and its reaction with $\mathrm{B}_2 \mathrm{H}_6$ and $\mathrm{AlCl}_3$.

Answer

LiH has sufficiently covalent character because lithium has smallest size.
$4\text{LiH}+\text{AlCl}_3\xrightarrow{\ \ \ \ \ \ \ \ \ \ }\text{LiAlH}_4+3\text{LiCl}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Lithium aluminium hydride}$
$2\text{LiH}+\text{B}_2\text{H}_6\xrightarrow{\ \ \ \ \ \ \ \ \ \ }\text{LiBH4}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^ \text{Lithium borohydride}$
$\text{LiAlH}_4$ and $\text{LiBH4}$ are used as reducing agents.

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