An object 3cm high is placed at a distance of 10cm in front of a converging mirror of focal length 20cm. Find the position, nature and size of the image formed.
Download our app for free and get started
Given: $h _1=3 cm, u =-10 cm, f =-20 cm$ We know that$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}=\frac{1}{\text{f}}-\frac{1}{\text{u}}=\frac{1}{(-20)}-\frac{1}{(-10)}$
$\frac{1}{20}+\frac{1}{10}=\frac{-1+2}{20}=\frac{1}{20}$
$\therefore\text{v}=20\text{cm}$
The image is formed at a distance of 20cm behind the mirror.$\text{m}=-\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\Rightarrow-\frac{(20)}{(-10)}=\frac{\text{h}_2}{3}$
$\Rightarrow\text{h}_2=6\text{cm}$
Image is 6cm in size, virtual and erect.
$\frac{1}{\text{v}}=\frac{1}{\text{f}}-\frac{1}{\text{u}}=\frac{1}{(-20)}-\frac{1}{(-10)}$
$\frac{1}{20}+\frac{1}{10}=\frac{-1+2}{20}=\frac{1}{20}$
$\therefore\text{v}=20\text{cm}$
The image is formed at a distance of 20cm behind the mirror.$\text{m}=-\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\Rightarrow-\frac{(20)}{(-10)}=\frac{\text{h}_2}{3}$
$\Rightarrow\text{h}_2=6\text{cm}$
Image is 6cm in size, virtual and erect.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionA man stands 10m in front of a large plane mirror. How far must the walk before he is 5m away from his image?
- 2When an object is placed at a distance of 50cm from a concave spherical mirror, the magnification produced is,$-\frac{1}{2}$ Where should the object be placed to get a magnification of, $-\frac{1}{5}?$View Solution
- 3View SolutionThe image of an object formed by a lens is of magnification - 1. If the distance between the object and its image is 60 cm, what is the focal length of the lens? If the object is moved 20 cm towards the lens, where would the image be formed? State reason and also draw a ray diagram in support of your answer.
- 4View SolutionGive three examples of materials that refract light rays. What happens to the speed of light rays when they enter these materials?
- 5View SolutionHow are power and focal length of a lens related? You are provided with two lenses of focal length 20cm and 40cm respectively. Which lens will you use to obtain more convergent light?
- 6View SolutionCalculate the image distance for an object of height 12mm at a distance of 0.20m from a concave lens of focal length 0.30 m, and state the nature and size of the image.
- 7View SolutionAn object is placed at a distance of 100cm from a converging lens of focal length 40cm.
- What is the nature of image?
- What is the position of image?
- 8View SolutionName the type of mirror used in the following situations.
- Headlights of a car.
- Side/rear-view mirror of a vehicle.
- Solar furnace.
- 9View SolutionA 4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 24 cm. The distance of the object from the lens is 16 cm. Find the position, size and nature of the image formed, using the lens formula.
- 10View SolutionAn object is placed between infinity and the pole of a convex mirror. Draw a ray diagram and also state the position, the relative size and the nature of the image formed.