An object is kept at a distance of 100cm from each of the above lenses. Calculate the (i) image distance and (ii) magnification in each of the two cases.
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To find the image for convex lens,$\text{u}=-100\text{cm}$
$\text{f}=50\text{cm}$
$\text{v}=\frac{(\text{f }\times\text{ u})}{(\text{f}-\text{u})}=100\text{cm}$
magnification is 1 for concave lens,$\text{u}=-100\text{cm}$
$\text{f}=-25\text{cm}$
$\text{v}=\frac{-(\text{f }\times\text{ u})}{(\text{f}+\text{u})}=-20\text{cm}$
magnification is $\frac{\text{v}}{\text{u}}$ that's $\frac{20}{100}$ So, $\text{m}=0.2$
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