An orbital electron in the ground state of hydrogen has magnetic moment $\mu_1$. This orbital electron is excited to $3^{rd}$ excited state by some energy transfer to the hydrogen atom. The new magnetic moment of the electron is $\mu_2$ , then
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$M=\frac{q L}{2 m}$
$\mathrm{M} \propto \mathrm{L} \quad \because \mathrm{L}=\frac{\mathrm{nh}}{2 \pi}$
$L \propto n$
$\therefore \mathrm{M} \propto \mathrm{n}$
Third exited state $n=4$
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