MCQ
An organic compound gives $0.220 g$ of $CO _2$ and $0.126 g$ of $H _2 O$ on complete combustion. If the $\%$ of carbon is 24 then the $\%$ hydrogen is $......\times 10^{-1} \cdot($ Nearest integer $)$
- A$51$
- B$52$
- ✓$56$
- D$53$
✓
Answer
Correct option: C.
$56$
c
Moles of $CO _2=\frac{0.22}{44}=\frac{1}{200}$
Moles of $CO _2=\frac{0.22}{44}=\frac{1}{200}$
$\therefore$ Moles of carbon
$=\left(\text { Moles of } CO _2\right) \times 1$
$=\frac{1}{200}$
$\therefore$ wt. of $C =\frac{1}{200} \times 12=0.06$
$\text { \% of } C =\frac{0.06}{ W } \times 100=24$
$( W = Wt \text {. of Organic Compound })$
$W =0.25$
Moles of $H _2 O =\frac{0.126}{18}=0.007$
$\therefore \text { Moles of } H \text { atom }=2 \times 0.007=0.014$
$\%$ of Hydrogen $=\frac{0.014 \times 1}{ W } \times 100$
$=\frac{0.014 \times 1}{0.25} \times 100$
$=5.6$
$=56 \times 10^{-1}$
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