$C{H_2} = C{H_2}\,\xrightarrow{{{O_2}/Ag}}\,X\,\xrightarrow{{473\,K}}\,Y$
$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{ether}]{{Mg}} $ $B\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D$
$CH_3 - O - CH(CH_3)_2 + HI \to$ નીપજ