|
લિસ્ટ $I$ (સમીકરણો) |
લિસ્ટ $II$ (પ્રક્રમનો પ્રકાર) |
| $A. \,\,K_p > Q$ | $(i)$ બિન સ્વયંભૂ |
| $B.\,\,\Delta G^o < RT ln Q$ | $(ii)$ સંતુલન |
| $C.\,\,K_p = Q$ | $(iii)$ સ્વયંભૂ અને ઉષ્માશોષક |
| $D.\,\,T>\frac{{\Delta H}}{{\Delta S}}$ | $(iv)$ સ્વયંભૂ |
\(\therefore\) Reaction is spontaneous
When \(\Delta G ^{\circ}\,<\, RT \ln Q , \Delta G ^{\circ}\) is positive, reverse reaction is feasible, thus reaction is nonspontaneous.
When \(K_p=Q\), rate of forward reaction \(=\) rate of backward reaction
\(\therefore\) Reaction is in equilibrium.
When \(T \Delta S \,>\,\Delta H , \Delta G\) will be negative only when \(\Delta H\) is positive.
Thus, the reaction is spontaneous and endothermic.
$CaO_{(s)}\,\, + \,\,{H_2}O_{(l)}\,\, \to \,\,Ca{(OH)_2}_{(s)}\,;\,\,\,........(i)$ $\,\Delta {H_{1.8\,^oC}} = \,\, - \,\,15.26\,\,K\,cal$
$H_2O_{(l)}\,$ $ \to $ ${H_{2{(g)}}}$ $+$ $\frac{1}{2}O_{2(g)}$ $\,\Delta {H_{1.8\,^oC}} = \,\, - \,\,68.37\,\,K\,cal$
$Ca_{(s)} + \frac{1}{2}O_{2(g)} = CaO_{(s)}$ $\,\Delta {H_{1.8\,^oC}} = \,\, \,\,-151.80\,\,K\,cal$