
Radius, $r=\frac{d}{2}=0.25 \times 10^{-3} m$
Compressional force, $F=50000 N$
Pressure at the tip of the anvil
$p=\frac{\text { Force }}{\text { Arear }}=\frac{F}{\pi r^{2}}$
$=\frac{50000}{\pi\left(0.25 \times 10^{-3}\right)^{2}}$
$=2.55 \times 10^{11} Pa$
Therefore, the pressure at the tip of the anvil is $2.55 \times 10^{11} \;Pa$

