Assertion : Angle of repose is equal to the angle of limiting friction. Reason : When the body is just at the point of motion,

Q: $Assertion$ : Angle of repose is equal to the angle of limiting friction. $Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.

b $\begin{array}{l} The\,{\rm{maximum}}\,value\,of\,static\,friction\,up\\ to\,which\,body\,does\,not\,move\,is\,called\,\\ {\rm{limiting}}\,friction.\\ \,\,\,\,\,\,\,\,\,Angle\,of\,repose\,is\,defined\,as\,the\,angle\\ \,\,\,\,\,\,\,\,\,\,of\,the\,inclined\,plane\,with\,horizontal\\ \,\,\,\,\,\,\,\,\,\,such\,that\,a\,body\,placed\,on\,it\,is\,just\,\\ \,\,\,\,\,\,\,\,\,\,begins\,to\,slide.\\ \,\,\,\,\,\,\,\,\,In\,{\rm{limiting}}\,{\rm{condition,}}\\ \,\,\,\,\,\,\,\,\,F = mg\sin \alpha \,and\,R = mg\cos \alpha \\ \,\,\,\,\,\,\,\,\,where\,\alpha - angle\,of\,repose. \end{array}$ $\begin{array}{l} \,\,So\,\frac{F}{R} = \tan \alpha \\ \,\,\,\,\,\,\,\,\,\,\therefore \frac{F}{R} = {\mu _2} = \tan \theta = \tan \alpha \,\,\,\left( {\tan \theta = {\mu _s}} \right)\\ \,\,\,\,\,\,\,\,\,\,or\,\theta = \alpha \\ \,\,\,\,\,\,\,\,\,\,i.e,.\,angle\,of\,friciton\, = \,angle\,of\,repose. \end{array}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

$Assertion$ : Angle of repose is equal to the angle of limiting friction.
$Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

AIIMS 2008, Medium

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free