Reason : Potential due to charge of outer shell remains same at every point inside the sphere.
$\mathrm{V}_{\mathrm{B}}=\frac{1}{4 \pi \varepsilon_{0}}\left(\frac{Q_{1}}{R_{1}}+\frac{Q_{2}}{R_{2}}\right)$
$\mathrm{V}_{\mathrm{B}}-\mathrm{V}_{\mathrm{A}}=\frac{1}{4 \pi \varepsilon_{0}} Q_{1}\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)$



