MCQ
Assuming fully decomposed, the volume of $C{O_2}$ released at $STP$ on heating $9.85\,g$ of $BaC{O_3}$ (Atomic mass of $Ba=137$) will be ................ $\mathrm{L}$
- A$0.84 $
- B$2.24$
- C$4.06$
- ✓$1.12$
✓
Answer
Correct option: D.
$1.12$
d
(d) $BaC{O_3} \to BaO + C{O_2} \uparrow $
(d) $BaC{O_3} \to BaO + C{O_2} \uparrow $
Molecular weight of $BaC{O_3} = 137 + 12 + 3 \times 16=197$
$197\,gm$ produces $22.4\,L$ at $S.T.P.$
$\therefore $ $9.85\,gm$ produces $\frac{{22.4}}{{197}} \times 9.85 = 1.12\,L$ at $S.T.P.$
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