MCQ
At $NTP$ the mass of one litre of air is $1.293\, gm.$ The value of specific gas constant will be ...... $J/K-gm$
- ✓$0.29$
- B$4.2$
- C$8.3$
- D$16.5$
At $NTP$,
Pressure, $P=1 \; atm =101325 Pa$
Temperature, $T=20^{\circ} C =\left(20+273.15^{-}\right) K =293.15 K$
Volume given, $V=1$ litre $=10^{-3} m ^{3}$
mass, $m=1.293 gm$
USe equation, $P V=m R T$
$(101325)\left(10^{-3}\right)$
$=(1.293) \cdot R \cdot(293.15)$
$R=0.2673 \; J / K - gm$
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