MCQ
At what speed should a source of sound move so that stationary observer finds the apparent frequency equal to half of the original frequency
  • A
    $\frac{v}{2}$
  • B
    $2v$
  • C
    $\frac{v}{4}$
  • $v$

Answer

Correct option: D.
$v$
d
(d) Frequency is decreasing (becomes half), it means source is going away from the observes. In this case frequency observed by the observer is

$n' = n\left( {\frac{v}{{v + {v_s}}}} \right)$ ==> $\frac{n}{2} = n\,\left( {\frac{v}{{v + {v_S}}}} \right)$ ==>${v_S} = v$

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