\({T_2} = \frac{{2{u_2}\sin ({{90}^o} - \theta )}}{g}\)\( = \frac{{2{u_2}\cos \theta }}{g}\)

\({T_1} = {T_2}\) 

\(\Rightarrow \frac{{2{u_1}}}{g} = \frac{{2{u_2}\cos \theta }}{g}\)

\(\Rightarrow {u_1} = {u_2}\cos \theta \)

\({H_1} = \frac{{u_1^2}}{{2g}}\)

\({H_2} = \frac{{u_2^2{{\sin }^2}({{90}^o} - \theta )}}{{2g}}\)

\(\therefore {H_2} = \frac{{u_2^2{{\cos }^2}\theta }}{{2g}}\)

\( \frac{{{H_1}}}{{{H_2}}} = \frac{{u_1^2/2g}}{{u_2^2{{\cos }^2}\theta /2g}}\)= 1 \([\,{u_1} = {u_2}\cos \theta \,]\)