\(9.8 \mathrm{gm}\) of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in \(100 \mathrm{L}\) sol. \(\Rightarrow 10^{-3} \mathrm{M}\) sol.
Mixture : \(40 L\) of \(10^{-3} \mathrm{M} \mathrm{NaOH}\) and \(10 \mathrm{L}\) of
\(10^{-3} \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) sol.
Final Conc. of \(OH^-=\frac{10^{-3}(40 \times 1-10 \times 1 \times 2)}{40+10}=6 \times 10^{-4} \mathrm{M}\)
\(\mathrm{pOH}=-\log \left(6 \times 10^{-4}\right)\)
\(=4-\log 6=4-0.60=3.40\)
\(\mathrm{pH}=14-3.40=10.60\)
$K_{sp}$ એ $AgCl = 1.2\times 10^{-10} \,K_{sp}$ એ $AgI = 1.7 \times 10^{-16}$
$K_{sp}$ એ $AgSCN = 7.1 \times 10^{-7} \,K_{sp}$ એ $AgBr = 3.5 \times 10^{-13}$