\(K _{ eq }=\frac{\left[ A ^{3+}\right]^2\left[ B ^{2-}\right]^3}{\left[ A _2 B _3\right]}=\frac{4 c ^2 \alpha^2 \times 27 c ^3 \alpha^3}{ c (1-\alpha)}\)
\(K _{ eq }=\frac{108 c ^5 \alpha^5}{ c } \alpha=\left(\frac{ K _{ eq }}{108 c ^4}\right)^{\frac{1}{5}}\)
[અહીં $K_b\,(NH_4OH) = 10^{-5}$ અને $log\,2 = 0.301$ ]