$E_{cell}^o\, = \,\frac{{2.303\,\,RT}}{{nF}}\log \,{K_c}$ $ = \,\frac{{0.0591}}{n}\,\log \,{K_c}$
$\therefore \,\,0.295\,\,V\,\, = \,\frac{{0.0591}}{2}\,\log \,\,{K_c}$
or $\,\log \,\,{K_c}\, = \,\frac{{2\, \times \,0.295}}{{0.0591}}\,\, = \,10$
or ${K_c}\, = \,1\, \times \,{10^{10}}$
વિદ્યુતવિભાજય $X$ શું છે?

${Zn}({s})+{Cu}^{2+}(0.02 {M}) \rightarrow {Zn}^{2+}(0.04 {M})+{Cu}({s})$
${E}_{\text {cell }}=...... \,\times 10^{-2} \,{~V}$ { (નજીકના પૂર્ણાંકમાં) }
${\left[ {E}_{{Cu} / {Cu}^{2+}}^{0}=-0.34\, {~V}, {E}_{2 {n} / {Zn}^{2+}}^{0}=+0.76 \,{~V}\right.}$
$\left.\frac{2.303 {RT}}{{F}}=0.059\, {~V}\right]$