Given, mass of body, \(m =50 kg ; g =10 ms ^{-2}\);
area, \(A =2 \times\) area of each thigh bone
\(=2 \times 10 cm ^2=20 \times 10^{-4} m ^2\)
(weight of the body is supported by two thigh bones)
Force, \(F\) = weight of the body \(= mg =50 \times 10\) \(=500 N\)
Pressure, \(P=\frac{\text { F orce }}{\text { Area }}=\frac{F}{A}=\frac{500}{20 \times 10^{-4}}\)
\(=2.5 \times 10^5 Pa\)