\(\frac{100 \times g }{ A _{2}}=\frac{ mg }{ A _{1}}\) \(........(1)\)
Let \(m\) mass can lift \(M _{0}\) in second case then
\(\frac{ M _{0} g }{16 A _{2}}=\frac{ mg }{ A _{1} / 16}\) \(.........(2)\)
\(\left\{\right.\) Since \(\left.A=\frac{\pi d ^{2}}{4}\right\}\)
From equation \((1)\) and \((2)\) we get
\(\frac{ M _{0}}{16.100}=16\)
\(\Rightarrow M _{0}=25600 \,kg\)
$\left( g =980 \,cm / s ^{2}\right)$