And as positive charge density is bigger in magnitude so its field along \(Y\) direction will be bigger than field of negative charge in \(X\) direction and this is evident in option \(1\) so it is correct.
$\left(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9\,N m ^2\,C ^{-2}, g=10\,m s ^{-2}\right)$