- ✓Magnetic meridian (or vertically north south)
- BPerpendicular to magnetic meridian
- CAt angle of ${45^o}$ to magnetic meridian
- DIt does not require any setting
$F=H \tan \theta$
where,
$F$, and $H$ are two uniform magnetic fields. Of the two uniform magnetic fields, one is the horizontal component of the earth's magnetic field, the other field is produced by a bar magnet The horizontal component of the earth's magnetic field is along the magnetic meridian i.e. the north south direction. So we first mark the magnetic meridian at the place where we are to do the experiment. We then place the magnetometer box such that the magnetic needle is also $g$ $N-S$ direction. The magnetometer is used in two positions $\tan A$ and $\tan B$
In the tan $A$ position the magnetometer arm is in the east west direction. And the needles points in the $N-S$ direction. The bar magnet is placed on the magnetometer arms with its axis along the $E-W$ direction.
In the tan $B$ position of the magnetometer, the arms are along $N-S$ direction. The bar magnet is placed on the arms of the instrument with its axis along $E-W$ direction.
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