(અહીં : $25^o C$ પર બાષ્પ દબાણના મૂલ્યો અનુક્રમે બેન્ઝિન $= 12.8\, kPa,$ ટોલ્યુઇન $= 3.85 \,kPa$)
\(\because \mathrm{YA}=\frac{\mathrm{P}^{\circ} \mathrm{A} \mathrm{X} \mathrm{A}}{\mathrm{P}}, \mathrm{YB}=\frac{\mathrm{P}^{\circ} \mathrm{BXB}}{\mathrm{P}}\)
\(\mathrm{X}_{\mathrm{A}}\) and \(\mathrm{X}_{\mathrm{B}}\) are same so mole fraction in vapour phase is directly proportional to the vapour pressure.
(આપેલ : $R =0.083\,L\,bar\,K ^{-1}\,mol ^{-1}$ )