Moles of \(H_2O\) \(=\,\frac {18}{18}\,=\,1\)
Mole fraction of \(NaOH\) \(=\,\frac {0.2}{1.2}\,=\,0.167\)
Molality \(=\,\frac {8}{40}\times \frac {1000}{18}=\,11.11\)
(બેન્ઝિન માટે $K_f $ $= 5.12 \,K\, kg\, mol^{-1}$)
$(R = 0.083 \,L\, bar \,mol^{-1}\, K{-1})$