Between the plates of a parallel plate condenser, a plate of thickness {t_1} and dielectric constant {k

Q: Between the plates of a parallel plate condenser, a plate of thickness ${t_1}$ and dielectric constant ${k_1}$ is placed. In the rest of the space, there is another plate of thickness ${t_2}$ and dielectric constant ${k_2}$. The potential difference across the condenser will be

a (a) Potential difference across the condenser $V = {V_1} + {V_2} = {E_1}{t_1} + {E_2}{t_2} = \frac{\sigma }{{{K_1}{\varepsilon _0}}}{t_1} + \frac{\sigma }{{{K_2}{\varepsilon _0}}}{t_2}$ $==>$ $V = \frac{\sigma }{{{\varepsilon _0}}}\left( {\frac{{{t_1}}}{{{K_1}}} + \frac{{{t_2}}}{{{K_2}}}} \right) = \frac{Q}{{A{\varepsilon _0}}}\left( {\frac{{{t_1}}}{{{K_1}}} + \frac{{{t_2}}}{{{K_2}}}} \right)$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Between the plates of a parallel plate condenser, a plate of thickness ${t_1}$ and dielectric constant ${k_1}$ is placed. In the rest of the space, there is another plate of thickness ${t_2}$ and dielectric constant ${k_2}$. The potential difference across the condenser will be

A$\frac{Q}{{A{\varepsilon _0}}}\left( {\frac{{{t_1}}}{{{k_1}}} + \frac{{{t_2}}}{{{k_2}}}} \right)$
B$\frac{{{\varepsilon _0}Q}}{A}\left( {\frac{{{t_1}}}{{{k_1}}} + \frac{{{t_2}}}{{{k_2}}}} \right)$
C$\frac{Q}{{A{\varepsilon _0}}}\left( {\frac{{{k_1}}}{{{t_1}}} + \frac{{{k_2}}}{{{t_2}}}} \right)$
D$\frac{{{\varepsilon _0}Q}}{A}({k_1}{t_1} + {k_2}{t_2})$

Medium

STD 11 Science
NEET
STD 12 - 2. Electric potential and capacitance
Physics

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