$(A)$ $n=4,1=1$ $(B)$ $\mathrm{n}=4,1=2$ $(C)$ $\mathrm{n}=3,1=1$ $(D)$ $\mathrm{n}=3,1=2$ $(E)$ $n=4,1=0$
નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.
$(A)$ $\mathrm{n}=4, \ell=1 \Rightarrow(\mathrm{n}+\ell)=5$
$(B)$ $\mathrm{n}=4, \ell=2 \Rightarrow(\mathrm{n}+\ell)=6$
$(C)$ $\mathrm{n}=3, \ell=1 \Rightarrow(\mathrm{n}+\ell)=4$
$(D$) $\mathrm{n}=3, \ell=2 \Rightarrow(\mathrm{n}+\ell)=5$
$(E)$ $\mathrm{n}=4, \ell=0 \Rightarrow(\mathrm{n}+\ell)=4$
For same value of $(n+\ell)$, orbital having higher value of $n$, will have more energy.
$(B) $>$ (A) $>$ (D) $>$ (E) $>$ (C)$