$Be =4:\, 1 s ^2\, 2 s ^2$
As we can see from the electronic configuration of $Be$ it is having completely filled outermost shell which is highly stable whereas in $B$ outermost shell consists of one electron which can be removed easily for attaining a stable configuration. Hence ionization energy of $B$ is greater than the ionization energy of $Be$.
સૂચિ $-I$ (પરમાણું ક્રમાંક) | સૂચિ $-II$ (આવર્તકોષ્ટકનો વિભાગ) |
$A$ $37$ | $I$ $p-$વિભાગ |
$B$ $78$ | $II$ $d-$વિભાગ |
$C$ $52$ | $III$ $f-$વિભાગ |
$D$ $65$ | $IV$ $s-$વિભાગ |
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