By using only two resistance coils-singly, in series, or in parallel one should be able to obtain resistances of $3$, $4$, $12$ and $16\, ohms$. The separate resistances of the coil are
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When resistances $4\,\Omega $ and $12\,\Omega $ are connected in series $ = 4 + 12 = 16\,\Omega $
When these resistance are connected in parallel.
$\frac{1}{{{R_P}}} = \frac{1}{4} + \frac{1}{{12}}$ $ \Rightarrow \,\,\,{R_P} = \frac{{4 \times 12}}{{4 + 12}} = \frac{{4 \times 12}}{{16}} = 3\,\Omega $
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