$S = \frac{{1.11 \times {{10}^{ - 8}} \times 1000}}{{111 \times 100}}mole/litre$
$ = {10^{ - 8}} \times {10^{ - 1}} = {10^{ - 9}}$
$K_{sp} = 4s^3 = 4 \times (10^{-9})^3 = 4 \times 10^{-27}$
$(I)\,H_2O$ $(II)\,\,NH_2$ $(III)\,\,H_2PO_4^-$ $(IV)\,\,HCO_3^-$
