(આપેલ $CaF _{2}$ નું મોલર દળ = $78 \,g mol ^{-1}$ )
\(S =\frac{2.34 \times 10^{-3}}{0.1 \times 78}=\frac{2.34}{78} \times 10^{-2}=3 \times 10^{-4}\,mol / L\)
\(K _{ sp }\left( CaF _{2}\right)=4 S ^{3}=4\left(3 \times 10^{-4}\right)^{3}\)
\(=108 \times 10^{-12}\)
\(=0.0108 \times 10^{-8}( mol / L )^{3}\)
$(1) 0.005\, M\, H_2SO_4\,(2) 0.1\, M\, Na_2SO_4\,(3) 10^{-2}\, M\, NaOH\,(4) 0.01 \,M\, HCl$