Calculate the amount of charge on capacitor of $4\, \mu\, {F}$. The internal resistance of battery is $1\, \Omega$ : (in $\mu {C}$)
JEE MAIN 2021, Diffcult
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On simplifying circuit we get
No current in upper wire.
$\therefore \quad {V}_{{AB}}=\frac{5}{4+1} \times 4=4 {v}$
$\therefore \quad \theta=\left({C}_{{eq}}\right) {v}$
$\Rightarrow 2 \times 4=8 \mu {C}$
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