Calculate the volume by volume percent solution formed by combining $18\ ml$ of pure hydrogen peroxide with water to make $630\ ml$ of solution.
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We know that, Volume $\%$ $=\Big(\frac{\text{ml of solute}}{\text{ml of solution}}\Big)\times100$
Given, Solute $= 18\ ml$ And, Solution $= 630\ ml\ X$ $ \%$ $\Big(\frac{18}{630}\Big)\times100$ $X$$ \% = 2.86$
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The teacher instructed three students $‘A’, ‘B’$ and $‘C’$ respectively to prepare a $50 \%$ (mass by volume) solution of sodium hydroxide $(NaOH)$. $‘A’$ dissolved $50g$ of $NaOH$ in $100\ mL$ of water, $‘B’$ dissolved $50\ g$ of $NaOH$ in $100\ g$ of water while $‘C’$ dissolved $50\ g$ of $NaOH$ in water to make $100\ mL$ of solution. Which one of them has made the desired solution and why?