\( \text { Mass of } \mathrm{CCl}_4=284 \mathrm{gm} \)
\( \text { Molar mass of } \mathrm{CCl}_4=154 \mathrm{~g} / \mathrm{mol} \)
\( \text { Moles of } \mathrm{CCl}_4=\frac{284}{154}=1.844 \mathrm{~mol} \)
\( \Delta \mathrm{H}_{\text {vap }}{ }^{\circ} \text { for } 1 \mathrm{~mole}=30.5 \mathrm{~kJ} / \mathrm{mol} \)
\( \Delta \mathrm{H}_{\text {vap }}{ }^{\circ} \text { for } 1.844 \mathrm{~mol}=30.5 \times 1.844 \)
\( \quad=56.242 \mathrm{~kJ}\)
પ્રક્રમ | $\Delta H / kJ\,mol ^{-1}$ | $\Delta S / J K^{-1}$ |
$A$ | $-25$ | $-80$ |
$B$ | $-22$ | $40$ |
$C$ | $25$ | $-50$ |
$D$ | $22$ | $20$ |
$H _{2( g )}+ Br _{2( g )} \rightarrow 2 HBr _{( g )}$
$H _{2}$ અને $H _{2}$ ની બંધઊર્જા અનુક્રમે $435\, kJ\, mol ^{-1}$ અને $192\, kJ mol\, ^{-1}$ છે. $HBr$ ની બંધઊર્જા ($kJ\, mol$ $^{-1}$ માં) જણાવો.