Charges -q,, q,,q are placed at the vertices A, B, C respectively of an equilateral triangle of side 'a' as shown in the figure. If

Q: Charges $-q,\, q,\,q$ are placed at the vertices $A$, $B$, $C$ respectively of an equilateral triangle of side $'a'$ as shown in the figure. If charge $-q$ is released keeping remaining two charges fixed, then the kinetic energy of charge $(-q)$ at the instant when it passes through the mid point $M$ of side $BC$ is

c $ \mathrm{U}_{\mathrm{i}}=-\frac{\mathrm{kq}^{2}}{\mathrm{a}}, \mathrm{U}_{\mathrm{f}} =-\frac{2 \mathrm{kq}^{2}}{\mathrm{a}}-\frac{2 \mathrm{kq}^{2}}{\mathrm{a}}+\frac{\mathrm{kq}^{2}}{\mathrm{a}} $ $=-\frac{3 \mathrm{kq}^{2}}{\mathrm{a}} $ $ \mathrm{W} =-\left(\mathrm{U}_{\mathrm{f}}-\mathrm{U}_{\mathrm{i}}\right) $ $ = - \left[ {\frac{{ - 3{\rm{k}}{{\rm{q}}^2}}}{{\rm{a}}} + \frac{{{\rm{k}}{{\rm{q}}^2}}}{{\rm{a}}}} \right] = \frac{{2{\rm{k}}{{\rm{q}}^2}}}{{\rm{a}}} = \frac{{{{\rm{q}}^2}}}{{2{ \in _0}\pi {\rm{a}}}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Charges $-q,\, q,\,q$ are placed at the vertices $A$, $B$, $C$ respectively of an equilateral triangle of side $'a'$ as shown in the figure. If charge $-q$ is released keeping remaining two charges fixed, then the kinetic energy of charge $(-q)$ at the instant when it passes through the mid point $M$ of side $BC$ is

A$\frac{{{q^2}}}{{8\pi { \in _0}a}}$
B$\frac{{{q^2}}}{{4\pi { \in _0}a}}$
C$\frac{{{q^2}}}{{2\pi { \in _0}a}}$
D$\frac{{{q^2}}}{{\pi { \in _0}a}}$

Medium

STD 11 Science
NEET
STD 12 - 2. Electric potential and capacitance
Physics

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