\(\Delta H = {(\Delta H_{f}^ \circ )_{CO}} + {(\Delta H_{f}^ \circ )_{{H_2}O}} - {(\Delta H_{f}^ \circ )_{C{O_2}}}\)
\(\Delta H = - 110.5 + ( - 241.8) - ( - 393.5) = + 41.2\,kJ\,mo{l^{ - 1}}\)
$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$
$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$
$C$(ગ્રેફાઈટ) $+$ $\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ પ્રક્રિયા માટે $\Delta H ^\theta$ શોધો.
પદાર્થ | $H _{2}$ | $C$(ગ્રેફાઈટ) | $C _{2} H _{6}( g )$ |
$\frac{\Delta_{ C } H ^{\Theta}}{ kJmol ^{-1}}$ | $-286.0$ | $-394.0$ | $-1560.0$ |
તો,ઈથેનની સર્જન એન્થાલ્પી ........