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Do the following activity to draw tangents to the circle without using the center of the circle.
- Draw a circle with radius 3.5 cm and take any point C on it.
- Draw chord CB and an inscribed angle CAB.
- With the center A and any convenient radius, draw an arc intersecting the sides of angle BAC in points M and N.
- Using the same radius, draw an arc intersecting the chord CB at point R.
- Taking the radius equal to d(MN) and center R, draw an arc intersecting the arc drawn in the previous step. Let D be the point of intersection of these arcs. Draw line CD. Line CD is the required tangent to the circle.
Complete the following table.
| No. | Equation | Is the equation a linear equation in 2 variables ? |
| 1 | 4m+3n=12 | Yes |
| 2 | 3x^(2)-7y=13 | |
| 3 | sqrt2x-sqrt5y=16 | |
| 4 | 0x+6y-3=0 | |
| 5 | 0.3 x+0y-36=0 | |
| 6 | (4)/(x)+(5)/(y)=4 | |
| 7 | 4xy-5y-8=0 |
For an $A.P., a = 12$ and $d = 4$ Complete the following activity to find $S_{30}$ of the $A.P$
Here, $a = 12, d = 4, S_{30} = ?$
→Here, $a = 12, d = 4, S_{30} = ?$
The distances covered by 250 public transport buses in a day is shown in the following frequency distribution table. Find the median of the distances.
| Distance (km) | 200-210 | 210-220 | 220-230 | 230-240 | 240-250 |
| No. of buses | 40 | 60 | 80 | 50 | 20 |
Find the correct answer from the alternatives given. Different expenditures incurred on the construction of a building were shown by a pie diagram. The expenditure $Rs. 45,000$ on cement was shown by a sector of central angle of $75^\circ$ . What was the total expenditure of the construction?
→The prices of different articles and demand for them is shown in the following frequency distribution table. Find the median of the prices.
Complete the following activity to find the sum of all two-digit numbers divisible by 8.
Two-digit numbers divisible by 8 are 16, 24, 32, ..., 88, 96.
Two-digit numbers divisible by 8 are 16, 24, 32, ..., 88, 96.
From fig., seg $PQ ||$ side $BC, AP = x + 3, PB = x – 3, AQ = x + 5, QC = x – 2,$ then complete the activity to find the value of $x.$
$\text { In } \triangle P Q B, P Q|| \text { side } B C$
$\frac{ AP }{ PB }=\frac{ AQ }{[} \quad \ldots[\ldots]$
$\frac{x+3}{x-3}=\frac{x+5}{[}$
$(x+3)[\quad]=(x+5)(x-3)$
$x^2+x-[\quad]=x^2+2 x-15$
$x=[$
→$\text { In } \triangle P Q B, P Q|| \text { side } B C$
$\frac{ AP }{ PB }=\frac{ AQ }{[} \quad \ldots[\ldots]$
$\frac{x+3}{x-3}=\frac{x+5}{[}$
$(x+3)[\quad]=(x+5)(x-3)$
$x^2+x-[\quad]=x^2+2 x-15$
$x=[$
Complete the following activity -
